(a+b)³ = a³+3a²b+3ab²+b³
(a+b)³ = a³+b³+3ab(a+b)
(a-b)³= a³-3a²b+3ab²-b³
(a-b)³= a³-b³-3ab(a-b)
a³+b³= (a+b) (a²-ab+b²)
a³+b³= (a+b)³-3ab(a+b)
a³-b³ = (a-b) (a²+ab+b²)
a³-b³ = (a-b)³+3ab(a-b)
(a² + b² + c²) = (a + b + c)² – 2(ab + bc + ca)
2 (ab + bc + ca) = (a + b + c)² – (a² + b² + c²)
(a + b + c)³ = a³ + b³ + c³ + 3 (a + b) (b + c) (c + a)
a³ + b³ + c³ – 3abc =(a+b+c)(a² + b²+ c²–ab–bc– ca)